What is the slope of a trend line that passes through the points (1,3) and (10,25)

Answer:22/9Step-by-step explanation:The slope of a line can be found by using the slope formula [tex]\frac{y_2-y_1}{x_2-x_1} \text{ where we have points } (x_1,y_1) \text{ and } (x_2,y_2) \text{ on the line }[/tex].Or what I like to do is line up the points and subtract vertically, then put 2nd difference over 1st difference. Like so:  ( 10  , 25)- (  1  ,    3)---------------- 9         22So the slope is 22/9.You could have done it the other way too. That is:  (1  ,  3)-(10 , 25)-------------9    -22So the slope is -22/-9 or just 22/9.