Q:

Write each equation in slope-intercept form of the equation of a line. Underline the slope and circle the y-intercept in each equation. a 3x+4y–12=0

Accepted Solution

A:
[tex]\bf 3x + 4y - 12 = 0\implies 4y-12 = -3x\implies 4y=-3x+12 \\\\\\ y = \cfrac{-3x+12}{4}\implies y = \cfrac{-3x}{4}+\cfrac{12}{4} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{4}}x\stackrel{\stackrel{b}{\downarrow }}{+3} \qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]