Q:

PLEASE HURRY Study these equations: f(x) = 2x – 8 g(x) = –5x What is h(x) = f(x)g(x)? h(x) = 10x2 – 40x h(x) = –10x2 + 40x h(x) = –10x + 40 h(x) = 10x – 40

Accepted Solution

A:
h(x)=[tex]-10x^{2}+40x[/tex]Step-by-step explanation:given ,[tex]f(x)=2x-8[/tex] given, [tex]g(x)=-5x[/tex]Given that [tex]h(x)=f(x)g(x)[/tex]Let [tex]t_{1}[/tex] be [tex]k_{1}x^{n_{1}}[/tex] where [tex]k_{1} \text{ and } n_{1} \text{ are constants}[/tex]Let [tex]t_{2}[/tex] be [tex]k_{2}x^{n_{2}}[/tex] where [tex]k_{2} \text{ and } n_{2} \text{ are constants}[/tex]We know that [tex]t_{1}\times t_{2}=k1\times x^{n_{1}}\times k2\times x^{n_{2}}[/tex]=[tex]k_1k_2x^{n_{1}+n_{2}}[/tex]So,[tex]h(x)=(2x-8)(-5x)[/tex]=[tex]-10x^{2}+40x[/tex]